A block of mass 
1 kg slides with velocity v = 6m/s on a frictionless horizontal surface and collides with a uniform vertical rod and sticks to it as shown. The rod is pivoted about O and swings as a result of the collision making angle θ before momentarily coming to rest. If the rod has mass M = 2kg and length I = lm, the value of θ is approximately (take g = 10m/s²)
Text Solution
Verified by ExpertsThe correct answer is:
C
Angular momentum conservation
Now using energy conservation
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